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y=5^x
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07 Apr 2021, 05:02
07 Apr 2021, 05:02
Expert Reply
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Question Stats:
80% (00:32) correct
19% (00:30) wrong based on 26 sessions
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\(y=5^x\)
x is a positive integer
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
x is a positive integer
Quantity A |
Quantity B |
\(5^{x+1}\) |
\(5y\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Re: y=5^x
[#permalink]
07 Apr 2021, 19:36
07 Apr 2021, 19:36
1
\(y=5^x\) & \(x\) is a +ve integer
Qt A
\(5^{x+1}\)
\(5^x * 5 \)
Qt B
\(5y\) = \(5^x * 5 \)
Qt A = Qt B
Answer C
Qt A
\(5^{x+1}\)
\(5^x * 5 \)
Qt B
\(5y\) = \(5^x * 5 \)
Qt A = Qt B
Answer C
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Re: y=5^x
[#permalink]
08 Apr 2021, 06:09
08 Apr 2021, 06:09
Carcass wrote:
\(y=5^x\)
x is a positive integer
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
x is a positive integer
Quantity A |
Quantity B |
\(5^{x+1}\) |
\(5y\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Given: \(y=5^x\)
Since \(y=5^x\), we can take Quantity B and replace \(y\) with \(5^x\) to get:
Quantity A: \(5^{x+1}\)
Quantity B: \(5y = (5)(5^x) = (5^1)(5^x) = 5^{x+1}\)
Answer: C
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