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Re: y=x^2-x and y=x-1 [#permalink]
a and b are integers a^2=b^3 what is the value of a and b
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Re: y=x^2-x and y=x-1 [#permalink]
a and b are integers a^2=b^3 what is the value of a and b
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Re: y=x^2-x and y=x-1 [#permalink]
eskay1981 wrote:
Answer is D. The relationship cannot be determined from the information given

If x = 1, then A =B,
if x = 2 then A > B, since both can't be right, answer is D.




It is a problem of two equations with two unknowns, x can only have to values in specific cases such as x = \sqrt{4}, which simplifying is not the case.
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y=x^2-x and y=x-1 [#permalink]
rx10 wrote:
\(y=x^2-x\) and \(y=x-1\)

\(x^2 - x = x - 1\)

\(x^2 - 2x + 1 = 0\)

\((x-1)^2 = 0\)

\(x = 1\)

Qt A = Qt B

Answer C


how can you equal both the equations ?
And when we can equal both the equations ?
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Re: y=x^2-x and y=x-1 [#permalink]
Expert Reply
if y = x^2-x and y IS x-1

therefore x-1 is in place of y

and we do have

x-1=x^2-x

rearrange on the first side

x-1+x-x^2

-x^2+2x-1=0

x^2-2x+1=0

I believe you lack of fundamental notions

see here please https://gre.myprepclub.com/forum/gre-ma ... 29264.html
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Re: y=x^2-x and y=x-1 [#permalink]
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