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(z^6)^x * z^3x
[#permalink]
17 Sep 2017, 11:50
17 Sep 2017, 11:50
Expert Reply
00:00
Question Stats:
90% (00:18) correct
9% (00:29) wrong based on 111 sessions
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Quantity A |
Quantity B |
\((z^6)^x \times z^{3x}\) |
\(z^{9x}\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Re: (z^6)^x * z^3x
[#permalink]
17 Sep 2017, 14:22
17 Sep 2017, 14:22
1
Carcass wrote:
Quantity A |
Quantity B |
\((z^6)^x * z^{3x}\) |
\(z^{9x}\) |
Given:
Quantity A: [(z^6)^x][z^(3x)]
Quantity B: z^(9x)
Apply Power of a Power rule to see that (z^6)^x = z^(6x).
So, we get:
Quantity A: [z^(6x)][z^(3x)]
Quantity B: z^(9x)
Next, apply Product rule to Quantity A to get:
Quantity A: z^(9x)
Quantity B: z^(9x)
Answer:
Show: ::
C
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Re: (z^6)^x * z^3x
[#permalink]
Updated on: 16 Jul 2019, 04:43
Updated on: 16 Jul 2019, 04:43
1
A: Simply
=z^6^X * Z^3x
=Z^6x * Z^3x
=Z^(6x+3x)
=Z^9x
C
=z^6^X * Z^3x
=Z^6x * Z^3x
=Z^(6x+3x)
=Z^9x
C
