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0<b<1
[#permalink]
03 Jul 2022, 21:35
03 Jul 2022, 21:35
Expert Reply
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Question Stats:
93% (00:15) correct
6% (00:15) wrong based on 16 sessions
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\(0<b<1\)
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Quantity A |
Quantity B |
\(b^2\) |
\(b^3 \) |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Part of the project: GRE QCQ & PS 3 Questions Every One DAILY Challenge - (2022)
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GRE Math Essentials (2022)
GRE Geometry Formulas for a Q170
GRE - Math Book
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GRE Math Essentials (2022)
GRE Geometry Formulas for a Q170
GRE - Math Book
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0<b<1
[#permalink]
04 Jul 2022, 06:02
04 Jul 2022, 06:02
1
Carcass wrote:
\(0<b<1\)
Quantity A |
Quantity B |
\(b^2\) |
\(b^3 \) |
We can solve this question using matching operations (see the video lesson below )
Given:
Quantity A: \(b^2\)
Quantity B: \(b^3 \)
Since \(b ≠ 0\), we can be certain that \(b^2\) is positive, which means we can safely divide both quantities by \(b^2\) to get:
Quantity A: \(1\)
Quantity B: \(b\)
Since \(0<b<1\), we know that Quantity A is greater.
Answer: A
RELATED VIDEO
Re: 0<b<1
[#permalink]
12 Jan 2023, 14:37
12 Jan 2023, 14:37
1
as the power increases, for decimas, the value decreases!
so, if b = 0.5, b^2 (0.25) > b^3 (0.125)
so, if b = 0.5, b^2 (0.25) > b^3 (0.125)
