GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
0 < x < 1
[#permalink]
Updated on: 25 Sep 2023, 06:21
Updated on: 25 Sep 2023, 06:21
Expert Reply
00:00
Question Stats:
86% (01:29) correct
13% (01:52) wrong based on 29 sessions
Hide Show timer Statistics
\(0 < x < 1
\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
\)
Quantity A |
Quantity B |
\(x-x^5\) |
\(x^2-x^3 \) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Part of the project: The Butler-GRE Daily New Quant and Verbal Questions to Practice (2023) - Gain 20 Kudos & Get FREE Access to GRE Prep Club TESTS
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
GRE - Math Book
Re: 0 < x < 1
[#permalink]
24 Sep 2023, 17:52
24 Sep 2023, 17:52
2
I'm a bit confused. Shouldn't the answer be d?
If x = -2
A: (-2) - (-2)^5 = -2 - (-32) = 30
B: (-2)^2 - (-2)^3 = 4 - (-8) = 12
A > B
If x = 2
A: (2) - (2)^5 = 2 - 32 = -30
B: (2)^2 - (2)^3 = 4 - 8 = -4
A < B
If x = -2
A: (-2) - (-2)^5 = -2 - (-32) = 30
B: (-2)^2 - (-2)^3 = 4 - (-8) = 12
A > B
If x = 2
A: (2) - (2)^5 = 2 - 32 = -30
B: (2)^2 - (2)^3 = 4 - 8 = -4
A < B
Re: 0 < x < 1
[#permalink]
25 Sep 2023, 06:21
25 Sep 2023, 06:21
Expert Reply
Sorry. It was in the title of the question that x is a fraction. I did not report the same constraint in the question. My bad
Given that 0 < x < 1
Assume x = 0.1
Quantity A: \(x - x^5\)
Now, when x is a positive fraction between 0 and 1 then as we increase power of x then value of the numbers starts decreasing
Ex: x = 0.1 , \(x^2\) = \(0.1^2\) = 0.01
So, \(x^5\) will be a very small number and will be less than x but will be positive
=> \(x - x^5\) ~ x > 0
Quantity A: \(x^2 - x^3\) = 0
Clearly, Quantity A > Quantity B
So, Answer will be A
Given that 0 < x < 1
Assume x = 0.1
Quantity A: \(x - x^5\)
Now, when x is a positive fraction between 0 and 1 then as we increase power of x then value of the numbers starts decreasing
Ex: x = 0.1 , \(x^2\) = \(0.1^2\) = 0.01
So, \(x^5\) will be a very small number and will be less than x but will be positive
=> \(x - x^5\) ~ x > 0
Quantity A: \(x^2 - x^3\) = 0
Clearly, Quantity A > Quantity B
So, Answer will be A
