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1+1/2+1/4+1/16
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06 Apr 2021, 01:53
06 Apr 2021, 01:53
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Quantity A |
Quantity B |
\(1+ \frac{1}{2} + \frac{1}{4 }+ \frac{1}{16} + \frac{1}{32 }+ \frac{1}{64} \) |
2 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
1+1/2+1/4+1/16
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06 Apr 2021, 09:54
06 Apr 2021, 09:54
Qt A
\(1+ \frac{1}{2} + \frac{1}{4 }+ \frac{1}{16} + \frac{1}{32 }+ \frac{1}{64} \)
This forms a geometric series.
Sum for geometric series = Sn = \(\frac{a(1-r^n)}{1-r}\)
a = 1 , r = \(\frac{1}{2}\) & n = 5
Sn = 1 - \(\frac{1}{32}\) / \(\frac{1}{2}\)
= \(\frac{31}{16}\) < 2
Qt B > Qt A
Answer B
\(1+ \frac{1}{2} + \frac{1}{4 }+ \frac{1}{16} + \frac{1}{32 }+ \frac{1}{64} \)
This forms a geometric series.
Sum for geometric series = Sn = \(\frac{a(1-r^n)}{1-r}\)
a = 1 , r = \(\frac{1}{2}\) & n = 5
Sn = 1 - \(\frac{1}{32}\) / \(\frac{1}{2}\)
= \(\frac{31}{16}\) < 2
Qt B > Qt A
Answer B
gmatclubot
1+1/2+1/4+1/16 [#permalink]
06 Apr 2021, 09:54
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