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(1/4)^-3(1/8)^-2(1/32)^-1=
[#permalink]
30 Aug 2021, 09:35
30 Aug 2021, 09:35
Expert Reply
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Question Stats:
73% (00:48) correct
26% (01:04) wrong based on 15 sessions
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\((\frac{1}{4})^{-3}(\frac{1}{8})^{-2}(\frac{1}{32})^{-1}=\)
A. \(\frac{1}{2}^{-6}\)
B. \(\frac{1}{2}^{-17}\)
C. \(\frac{1}{4}^{-9}\)
D. \(\frac{1}{4}^{-11}\)
E. \(\frac{1}{8}^{-6}\)
Kudos for the right answer and explanation
Question part of the project GRE Quant/Math Extreme Challenge Daily (2021) Edition
GRE - Math Book
A. \(\frac{1}{2}^{-6}\)
B. \(\frac{1}{2}^{-17}\)
C. \(\frac{1}{4}^{-9}\)
D. \(\frac{1}{4}^{-11}\)
E. \(\frac{1}{8}^{-6}\)
Kudos for the right answer and explanation
Question part of the project GRE Quant/Math Extreme Challenge Daily (2021) Edition
GRE - Math Book
Re: (1/4)^-3(1/8)^-2(1/32)^-1=
[#permalink]
30 Aug 2021, 19:29
30 Aug 2021, 19:29
1
\((\frac{1}{4})^{-3}(\frac{1}{8})^{-2}(\frac{1}{32})^{-1}\)
\(4^3 * 8^2 * 32\)
\(2^6 * 2^6 * 2^5\)
\(2^{17}\)
\(\frac{1}{2}^{-17}\)
Answer B
\(4^3 * 8^2 * 32\)
\(2^6 * 2^6 * 2^5\)
\(2^{17}\)
\(\frac{1}{2}^{-17}\)
Answer B
gmatclubot
Re: (1/4)^-3(1/8)^-2(1/32)^-1= [#permalink]
30 Aug 2021, 19:29
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