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$1 / 3+2 / 5=p$, and, in lowest terms, $p=a / b$, where $a$ and $b$ ar
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12 Nov 2025, 02:02
12 Nov 2025, 02:02
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Question Stats:
75% (00:47) correct
25% (00:59) wrong based on 12 sessions
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$\(\frac{1 }{ 3}+\frac{2 }{ 5}=p\)$, and, in lowest terms, $\(p=\frac{a }{ b}\)$, where $a$ and $b$ are positive integers.
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Quantity A |
Quantity B |
b |
10 |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
- Part of the project: GRE Daily Quant Challenge - Topic-Wise 2025!!!
- Also replying to the unanswered questions
$1 / 3+2 / 5=p$, and, in lowest terms, $p=a / b$, where $a$ and $b$ ar
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22 Nov 2025, 15:24
22 Nov 2025, 15:24
1
\(\frac{1}{3}\) + \(\frac{2}{5}\), when combined into like terms, results in \(\frac{11}{15}\). Since this can't be made in lower terms, then a=11 and b=15. 15 > 10, so Quantity A (b=15) > Quantity B (10).
Answer: A) Quantity A is greater.
Answer: A) Quantity A is greater.
gmatclubot
$1 / 3+2 / 5=p$, and, in lowest terms, $p=a / b$, where $a$ and $b$ ar [#permalink]
22 Nov 2025, 15:24
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