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1/1+1/1-1/3
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Updated on: 30 Jun 2018, 10:11
Updated on: 30 Jun 2018, 10:11
1
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Question Stats:
100% (00:26) correct
0% (00:00) wrong based on 8 sessions
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\(\frac{1}{1 + \frac{1}{1 - \frac{1}{3}}\)
A \(\frac{2}{5}\)
B \(\frac{4}{7}\)
C \(\frac{2}{3}\)
D \(\frac{3}{4}\)
E \(\frac{5}{6}\)
A \(\frac{2}{5}\)
B \(\frac{4}{7}\)
C \(\frac{2}{3}\)
D \(\frac{3}{4}\)
E \(\frac{5}{6}\)
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1/1+1/1-1/3
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16 Sep 2022, 09:09
16 Sep 2022, 09:09
We need to find the value of \(\frac{1}{1 + \frac{1}{1 - \frac{1}{3}}\)
\(\frac{1}{1 + \frac{1}{1 - \frac{1}{3}}\)
= \(\frac{1}{1 + \frac{1}{\frac{3 - 1}{3}}\)
= \(\frac{1}{1 + \frac{1}{\frac{2}{3}}\)
= \(\frac{1}{1 + \frac{3}{2}\)
= \(\frac{1}{\frac{ 2 + 3}{2}\)
= \(\frac{1}{\frac{5}{2}\)
= \(\frac{2}{5}\)
So, Answer will be A
Hope it helps!
\(\frac{1}{1 + \frac{1}{1 - \frac{1}{3}}\)
= \(\frac{1}{1 + \frac{1}{\frac{3 - 1}{3}}\)
= \(\frac{1}{1 + \frac{1}{\frac{2}{3}}\)
= \(\frac{1}{1 + \frac{3}{2}\)
= \(\frac{1}{\frac{ 2 + 3}{2}\)
= \(\frac{1}{\frac{5}{2}\)
= \(\frac{2}{5}\)
So, Answer will be A
Hope it helps!
