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1 < a < b < 0

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Carcass
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1 < a < b < 0 [#permalink] New post   06 May 2022, 01:18
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\(− 1 < a < b < 0\)


Quantity A
Quantity B
\(a+b\)
\( a-b\)



A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given

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B
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GreenlightTestPrep
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Re: 1 < a < b < 0 [#permalink] New post   06 May 2022, 06:16
1
Carcass wrote:
\(− 1 < a < b < 0\)


Quantity A
Quantity B
\(a+b\)
\( a-b\)




We can solve this question using matching operations (see the video lesson below )

Given:
Quantity A: \(a+b\)
Quantity B: \( a-b\)

Add \(b\) to both quantities:
Quantity A: \(a+2b\)
Quantity B: \( a\)

Subtract \(a\) from both quantities:
Quantity A: \(2b\)
Quantity B: \(0\)

Since it's given that \(b\) is negative, we can conclude that \(2b\) is negative, which means Quantity B is greater.

Answer: B

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Re: 1 < a < b < 0 [#permalink]
06 May 2022, 06:16
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