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1/x + 1/x

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Carcass
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1/x + 1/x [#permalink] New post   20 Oct 2018, 06:48
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\(x \neq 0\)

Quantity A
Quantity B
\(\frac{1}{x} + \frac{1}{x}\)
\(\frac{1}{x}*\frac{1}{x}\)


Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
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D
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pranab223
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Re: 1/x + 1/x [#permalink] New post   20 Oct 2018, 20:08
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Carcass wrote:
\(x \neq 0\)

Quantity A
Quantity B
\(\frac{1}{x} + \frac{1}{x}\)
\(\frac{1}{x}*\frac{1}{x}\)


Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.



Value of x\neq 0, so x can be any value except 0

Qty A = \(\frac{1}{x} + \frac{1}{x}= \frac{1}{x}\)

Qty B = \(\frac{1}{x}*\frac{1}{x} = \frac{1}{x^2}\)

If x= 1, then QTY A = QTY B

If x= 2 then QTY A > QTY B

Hence the option is D
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Re: 1/x + 1/x [#permalink] New post   24 Oct 2018, 06:14
I got this.
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Re: 1/x + 1/x [#permalink] New post   24 Oct 2018, 10:29
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Carcass wrote:
\(x \neq 0\)

Quantity A
Quantity B
\(\frac{1}{x} + \frac{1}{x}\)
\(\frac{1}{x}*\frac{1}{x}\)



We can also solve this question using matching operations

Given:
Quantity A: 1/x + 1/x
Quantity B: (1/x)(1/x)

Simplify both quantities:
Quantity A: 2/x
Quantity B: 1/x²

Since we can be certain that x² is POSITIVE, we can safely multiply both quantities by x² to get:
Quantity A: 2x²/x
Quantity B: 1

Simplify:
Quantity A: 2x
Quantity B: 1

For "kicks," let's totally simplify the question by dividing both quantities by 2 to get:
Quantity A: x
Quantity B: 1/2

Since there are no restrictions on x (other than x ≠ 0), we can see that:
x COULD equal 1/2 in which case the quantities are EQUAL
x COULD equal 1 in which case Quantity A is GREATER
x COULD equal -1 in which case Quantity B is GREATER

Answer: D

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Re: 1/x + 1/x [#permalink] New post   02 Jan 2019, 09:11
pranab01 wrote:
Carcass wrote:
\(x \neq 0\)

Quantity A
Quantity B
\(\frac{1}{x} + \frac{1}{x}\)
\(\frac{1}{x}*\frac{1}{x}\)


Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.



Value of x\neq 0, so x can be any value except 0

Qty A = \(\frac{1}{x} + \frac{1}{x}= \frac{1}{x}\)

Qty B = \(\frac{1}{x}*\frac{1}{x} = \frac{1}{x^2}\)

If x= 1, then QTY A = QTY B

If x= 2 then QTY A > QTY B

Hence the option is D


Please fix
Qty A = \(\frac{1}{x} + \frac{1}{x}= \frac{2}{x}\)
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Re: 1/x + 1/x [#permalink] New post   02 Jan 2019, 09:18
GreenlightTestPrep wrote:

Since we can be certain that x² is POSITIVE, we can safely multiply both quantities by x² to get:
Quantity A: 2x²/x
Quantity B: 1

Simplify:
Quantity A: 2x
Quantity B: 1



As we do not know about x, positive or negative, can we write 2x²/x = 2x
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Re: 1/x + 1/x [#permalink] New post   02 Jan 2019, 09:44
AE wrote:
As we do not know about x, positive or negative, can we write 2x²/x = 2x


That works too!

Cheers,
Brent
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Re: 1/x + 1/x [#permalink] New post   30 Mar 2021, 08:49
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