We need to compare $\(10^{12}+2^{12}\)$ (Column A) with $\(12^{12}\)$ (Column B).

Taking ratio of column A \& column B, if the simplified value comes out to be

1. less than 1 then denominator value so column $B$ value is greater

2. greater than 1 , numerator so column $A$ value is greater

3. 1 then numerator and denominator values so column $A \&$ column $B$ values are equal.

Now the given expressions when simplified give values as $\(10^{12}=(2 \times 5)^{12}=2^{12} \times 5^{12} \& 12^{12}=\left(2^2 \times 3\right)^{12}=2^{24} \times 3^{12}\)$

so, the ratio comes out to be

$\(\frac{10^{12}+2^{12}}{12^{12}}=\)

\(\frac{2^{12} \times 5^{12}+2^{12}}{2^{24} \times 3^{12}}\)

\(\frac{2^{12}\left(5^{12}+1\right)}{2^{24} \times 3^{12}}=\)

\(\frac{5^{12}+1}{2^{12} \times 3^{12}}=\)

\(\frac{5^{12}+1}{6^{12}}<1\)


\(\left(\because \frac{x^a}{x^b}=x^{a-b} \&\left(x^a\right)^b=x^{a b}\right)\)$

Hence column B has greater quantity, so the answer is (B).