OE


The number of machines working, with their number hours of work, is directly proportional with the amount of work done.

So, we get $\(\frac{m_1 \times h_1}{w_1}=\frac{m_2 \times h_2}{w_2}\)$, where $\(m_1, h_1 \& w_1\)$ is the number of machines, the number of hours it takes and the amount of work done respectively. Same is for $\(\mathrm{m}_2, \mathrm{~h}_2 \& \mathrm{w}_2\)$ for machine 2 .

Here we have $\(\mathrm{m}_1=10, \mathrm{~h}_1=8, \mathrm{w}_1=200 \& \mathrm{~m}_2=24, \mathrm{~h}_2=?, \mathrm{w}_2=180\)$, substituting these values in the formula we get $\(\frac{10 \times 8}{200}=\frac{24 \times h_2}{180} \Rightarrow h_2=\frac{10 \times 8 \times 180}{200 \times 24}=3\)$ hours

Hence the number of hours that 24 machines would take to produce 180 pairs of shoes is 3 hours, so the answer is (C).