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14/42^4 or 1/3*2/9
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28 Dec 2021, 06:21
28 Dec 2021, 06:21
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Question Stats:
60% (00:58) correct
40% (01:09) wrong based on 40 sessions
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Quantity A |
Quantity B |
\((\frac{14}{42})^4 \) |
\(\frac{1}{3} \times \frac{2}{9} \times \frac{3}{(-6)} \times \frac{(-1)}{3}\) |
The quantity in Column A is greater
The quantity in Column B is greater
The two quantities are equal
The relationship cannot be determined from the information given
14/42^4 or 1/3*2/9
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28 Dec 2021, 10:17
28 Dec 2021, 10:17
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Qt A
\((\frac{14}{42})^4 \)
\(3^{-4}\)
Qt B
\(\frac{1}{3} × \frac{2}{9} × \frac{3}{(−6)} × \frac{(−1)}{3}\)
\(\frac{2}{27} * \frac{1}{6}\)
\(\frac{1}{81}\)
\(3^{-4}\)
Qt A = Qt B
Answer C
\((\frac{14}{42})^4 \)
\(3^{-4}\)
Qt B
\(\frac{1}{3} × \frac{2}{9} × \frac{3}{(−6)} × \frac{(−1)}{3}\)
\(\frac{2}{27} * \frac{1}{6}\)
\(\frac{1}{81}\)
\(3^{-4}\)
Qt A = Qt B
Answer C
gmatclubot
14/42^4 or 1/3*2/9 [#permalink]
28 Dec 2021, 10:17
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