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-15<x<-11

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-15<x<-11 [#permalink] New post   08 Feb 2024, 00:24
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\(-15<x<-11\)


Quantity A
Quantity B
\(\dfrac{1}{x^5}\)
\(\dfrac{1}{x^3}\)



A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.



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Arjun12
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-15<x<-11 [#permalink] New post   11 Feb 2024, 23:28
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as x is not equal to 1, we can take any value greater than 1 to establish the equation.
Let's not take the negative sign for some time, for any x > 1, x^5 > x^3.
Similarly,
[1][/x^5] <[1][/x^3]
If we multiply by the negative sign both sides equality sign will change,
Hence [1/x^5] > [1/x^3]

Ans. A
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gmatclubot
-15<x<-11 [#permalink]
11 Feb 2024, 23:28
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