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18-4/5+1/2
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31 Mar 2021, 02:22
31 Mar 2021, 02:22
Expert Reply
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Question Stats:
73% (00:47) correct
26% (00:41) wrong based on 23 sessions
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Quantity A |
Quantity B |
\(18-\frac{4}{5}+\frac{1}{2}\) |
\(18-\frac{1}{2}+\frac{4}{5} \) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
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Re: 18-4/5+1/2
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31 Mar 2021, 05:50
31 Mar 2021, 05:50
Carcass wrote:
Quantity A |
Quantity B |
\(18-\frac{4}{5}+\frac{1}{2}\) |
\(18-\frac{1}{2}+\frac{4}{5} \) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
We can solve this question using matching operations (my favorite Quantitative Comparison strategy)
Given:
Quantity A: \(18-\frac{4}{5}+\frac{1}{2}\)
Quantity B: \(18-\frac{1}{2}+\frac{4}{5} \)
Subtract 18 from both quantities:
Quantity A: \(-\frac{4}{5}+\frac{1}{2}\)
Quantity B: \(-\frac{1}{2}+\frac{4}{5} \)
Add \(\frac{4}{5}\) to both quantities:
Quantity A: \(\frac{1}{2}\)
Quantity B: \(-\frac{1}{2}+\frac{8}{5} \)
Add \(\frac{1}{2}\) to both quantities:
Quantity A: \(\frac{2}{2}=1\)
Quantity B: \(\frac{8}{5} \)
Answer: B
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gmatclubot
Re: 18-4/5+1/2 [#permalink]
31 Mar 2021, 05:50
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