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2*10^1+3*10^0+4*10^-1
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01 Apr 2019, 04:19
01 Apr 2019, 04:19
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Question Stats:
80% (00:54) correct
19% (01:57) wrong based on 51 sessions
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Quantity A |
Quantity B |
\((2*10^1+3*10^0+4*10^{-1}+5*10^{-2})\) |
\((1*10^{-3}+2*10^{-2}+3*10^{-1}+4*10^0+5*10^1)\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Re: 2*10^1+3*10^0+4*10^-1
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01 Apr 2019, 07:12
01 Apr 2019, 07:12
1
a: 20+3+0.4+0.05 and b:..+.....+...+50
so obviously b is the answer.
so obviously b is the answer.
2*10^1+3*10^0+4*10^-1
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16 Aug 2024, 04:12
16 Aug 2024, 04:12
1
POLASH106 wrote:
a: 20+3+0.4+0.05 and b:..+.....+...+50
so obviously b is the answer.
so obviously b is the answer.
Any number^0=1 so just calculate the value of numbers^any non negative power of 10 as everything else will fall in decimal places. As 50>20 B will be greater than A. Note this is an easy shortcut only because all numbers are being multiplied to different powers of 10.
