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2^-4/4^-2 or sqrt of 64/-2^3
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Updated on: 28 May 2023, 09:32
Updated on: 28 May 2023, 09:32
Expert Reply
00:00
Question Stats:
84% (00:53) correct
15% (00:36) wrong based on 19 sessions
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Quantity A |
Quantity B |
\(\frac{2^{-4}}{4^{-2}}\) |
\(\frac{\sqrt{64}}{-2^3}\) |
A Quantity A is greater.
B Quantity B is greater.
C The two quantities are equal.
D The relationship cannot be determined from the information given.
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2^-4/4^-2 or sqrt of 64/-2^3
[#permalink]
28 May 2023, 09:32
28 May 2023, 09:32
Expert Reply
If you know the exponents rule as a cold, this question is not difficult at all
A can be written as
\(\frac{\frac{1}{2^4}}{\frac{1}{4^2}}=\frac{\frac{1}{16}}{\frac{1}{16}}=\frac{16}{16}=1\)
B is \(\frac{8}{-2^3}=\frac{8}{-8}=-1\)
A is the answer
A can be written as
\(\frac{\frac{1}{2^4}}{\frac{1}{4^2}}=\frac{\frac{1}{16}}{\frac{1}{16}}=\frac{16}{16}=1\)
B is \(\frac{8}{-2^3}=\frac{8}{-8}=-1\)
A is the answer
gmatclubot
2^-4/4^-2 or sqrt of 64/-2^3 [#permalink]
28 May 2023, 09:32
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