--------ASIDE------------------------
Many students will fail to correctly simplify the terms on the left side of the given equation.
Notice that k + k + k + k = 4k
And x² + x² + x² + x² = 4x²
And 2m + 2m + 2m + 2m = 4(2m) = 8m
Likewise, \(2^n + 2^n + 2^n + 2^n = 4(2^n)\)
-----ONTO THE QUESTION!!---------------


GIVEN: \(2^n + 2^n + 2^n + 2^n = 4^{n+3}\)

Simplify left side: \(4(2^n) = 4^{n+3}\)

Rewrite both 4's as follows: \((2^2)(2^n) = (2^2)^{n+3}\)

Simplify both sides: \(2^{2+n} = 2^{2n+6}\)

Since we now have the same base on each side, we can conclude that: \(2+n = 2n+6\)

Solve to get: \(n = -4\)

We have:
QUANTITY A: -4
QUANTITY B: 4

Answer: B

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