GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
2 ≤ x ≤ 10 y > 3
[#permalink]
27 Mar 2020, 02:40
27 Mar 2020, 02:40
Expert Reply
2
Bookmarks
00:00
Question Stats:
69% (01:12) correct
30% (01:02) wrong based on 89 sessions
Hide Show timer Statistics
\(2 ≤ x ≤ 10\)
\(y > 3\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
\(y > 3\)
Quantity A |
Quantity B |
\(x-y\) |
\(xy\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Re: 2 ≤ x ≤ 10 y > 3
[#permalink]
27 Mar 2020, 03:41
27 Mar 2020, 03:41
1
Carcass wrote:
\(2 ≤ x ≤ 10\)
\(y > 3\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
\(y > 3\)
Quantity A |
Quantity B |
\(x-y\) |
\(xy\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Here,
By looking at the equation, we can find out
x and y are positive numbers
and product of two positive numbers will always be greater than the substraction of the same positive numbers
i.e. (x-y) < xy
Option B
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
2 ≤ x ≤ 10 y > 3
[#permalink]
30 Mar 2020, 06:30
30 Mar 2020, 06:30
1
Carcass wrote:
\(2 ≤ x ≤ 10\)
\(y > 3\)
\(y > 3\)
Quantity A |
Quantity B |
\(x-y\) |
\(xy\) |
We can solve this question using matching operations (my favorite Quantitative Comparison strategy)
Given:
Quantity A: \(x-y\)
Quantity B: \(xy\)
Add \(y\) to both quantities to get:
Quantity A: \(x\)
Quantity B: \(xy+y\)
Factor Quantity B as follows:
Quantity A: \(x\)
Quantity B: \(y(x+1)\)
Since it is given that \(x\) is positive, we can also be certain that \(x+1\) is positive, which means we can safely divide both quantities by \(x+1\) to get:
Quantity A: \(\frac{x}{x+1}\)
Quantity B: \(y\)
Since \(x\) is positive, and since \(x<x+1\), we can be certain that \(\frac{x}{x+1}<1\)
We get:
Quantity A: Some number that's less than 1
Quantity B: \(y\) (which is some number greater than 3)
Answer: B
RELATED VIDEO
