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2/x = 2-x / x-2

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Farina
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2/x = 2-x / x-2 [#permalink] New post   24 Jul 2020, 05:54
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\(\frac{2}{x} = \frac{2-x }{ x-2}\)

Quantity A
Quantity B
x
0



A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
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B
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GreenlightTestPrep
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Re: 2/x = 2-x / x-2 [#permalink] New post   24 Jul 2020, 06:26
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Farina wrote:
\(\frac{2}{x} = \frac{2-x }{ x-2}\)

Quantity A
Quantity B
x
0



A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.


Given: \(\frac{2}{x} = \frac{2-x }{ x-2}\)

Rewrite the right side as follows: \(\frac{2}{x} = \frac{-1(-2+x)}{x-2}\)

In other words: \(\frac{2}{x} = \frac{-1(x-2)}{x-2}\)

Simplify the right side to get: \(\frac{2}{x} = -1\)

From this we can conclude that \(x = -2\), which means Quantity B is greater.

Answer: B

Cheers,
Brent
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Farina
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Re: 2/x = 2-x / x-2 [#permalink] New post   24 Jul 2020, 06:33
GreenlightTestPrep wrote:
Farina wrote:
\(\frac{2}{x} = \frac{2-x }{ x-2}\)

Quantity A
Quantity B
x
0



A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.


Given: \(\frac{2}{x} = \frac{2-x }{ x-2}\)

Rewrite the right side as follows: \(\frac{2}{x} = \frac{-1(-2+x)}{x-2}\)

In other words: \(\frac{2}{x} = \frac{-1(x-2)}{x-2}\)

Simplify the right side to get: \(\frac{2}{x} = -1\)

From this we can conclude that \(x = -2\), which means Quantity B is greater.

Answer: B

Cheers,
Brent


Thanks, it was a great explanation
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gmatclubot
Re: 2/x = 2-x / x-2 [#permalink]
24 Jul 2020, 06:33
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