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20 people attended a meeting in Washington. In how many ways can a t
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29 Oct 2024, 01:12
29 Oct 2024, 01:12
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75% (02:44) correct
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20 people attended a meeting in Washington. In how many ways can a team of 10 people be made if 4 people refuse to be in the team and 6 particular people should be selected in the team?
A. 105
B. 210
C. 420
D. 840
E. 960
A. 105
B. 210
C. 420
D. 840
E. 960
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Re: 20 people attended a meeting in Washington. In how many ways can a t
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29 Oct 2024, 08:52
29 Oct 2024, 08:52
To form a team of 10 people from 20 attendees, where 4 people refuse to join and 6 specific people must be included, we start by selecting the required members.
Since 6 particular people must be on the team, that leaves us needing 4 more members.
With the 4 people refusing to join, we only have 16 potential candidates left (20 total minus the 4 refusals).
From these 16 people, we need to choose 4 to complete the team.
Using combinations,
The number of ways to choose 4 people from 16 is calculated as 210. Thus, the answer is 210.
Since 6 particular people must be on the team, that leaves us needing 4 more members.
With the 4 people refusing to join, we only have 16 potential candidates left (20 total minus the 4 refusals).
From these 16 people, we need to choose 4 to complete the team.
Using combinations,
The number of ways to choose 4 people from 16 is calculated as 210. Thus, the answer is 210.
Re: 20 people attended a meeting in Washington. In how many ways can a t
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30 Oct 2024, 04:54
30 Oct 2024, 04:54
Carcass, can you please advise whether we should use the following formula?
nCr = n! / r! * (n - r)!
According to this formula, I will not be able to get 210.
nCr = n! / r! * (n - r)!
According to this formula, I will not be able to get 210.
