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2ab5 is a four-digit number divisible by 25. If the number f
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14 Apr 2018, 02:40
14 Apr 2018, 02:40
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Question Stats:
81% (01:16) correct
18% (01:21) wrong based on 49 sessions
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2ab5 is a four-digit number divisible by 25. If the number formed from the two digits ab is a multiple of 13, then ab =
(A) 10
(B) 25
(C) 52
(D) 65
(E) 75
(A) 10
(B) 25
(C) 52
(D) 65
(E) 75
Re: 2ab5 is a four-digit number divisible by 25. If the number f
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20 Apr 2018, 03:46
20 Apr 2018, 03:46
2
Since it is given that ab is divisible by \(13\) we should first check ans choices to eliminate options that are not divisible by \(13\):
option a: \(10\) is below \(13\)so it is not divisible by \(13\)
option b: \(25\) is one less than \(26\) so it is also not divisible by \(13\)
option c: \(52\) is divisible by \(13\) so let us see if the total number replaced by \(52\) for the position ab is divisible by \(25\)
\(\frac{2525}{25}= 101\)
option C
option a: \(10\) is below \(13\)so it is not divisible by \(13\)
option b: \(25\) is one less than \(26\) so it is also not divisible by \(13\)
option c: \(52\) is divisible by \(13\) so let us see if the total number replaced by \(52\) for the position ab is divisible by \(25\)
\(\frac{2525}{25}= 101\)
option C
Re: 2ab5 is a four-digit number divisible by 25. If the number f
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17 Jul 2018, 12:26
17 Jul 2018, 12:26
2
Carcass wrote:
2ab5 is a four-digit number divisible by 25. If the number formed from the two digits ab is a multiple of 13, then ab =
(A) 10
(B) 25
(C) 52
(D) 65
(E) 75
(A) 10
(B) 25
(C) 52
(D) 65
(E) 75
Note :
ab is a multiple of 13. So, we can eliminate Option A, B, and E.
Option C:
2525 / 25.........clearly divisible. So, ab must be 52.
The best answer is C.
