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2x + 2 [#permalink]
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Expert Reply
\(\sqrt{2x + 2} −\sqrt{x − 3} = 2\)
\(\sqrt{2x + 2} = 2 + \sqrt{x − 3}\)

\((\sqrt{2x + 2})^2 = (2 + (\sqrt{x − 3})^2\)

Manipulation + double product + considering that the square root goes away with the exponent ^2

\((2x + 2) = 4 + (x - 3) + 4\sqrt{x-3}\)
\(x + 1 = 4\sqrt{x-3}\)

Squaring again;
\(x^2 + 2x + 1 = 16(x - 3)\)
\(x^2 + 2x + 1 = 16x - 49\)
\(x^2 - 14x + 49 = 0\)

At this point, you find simply the roots of the equation.

i hope now is more clear
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Re: 2x + 2 [#permalink]
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Thanks Carcass got it
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