Given the system of equations:

$$
\(\begin{gathered}
2 x+5 y=14 \\
x+3 y=20
\end{gathered}\)
$$


First, multiply the second equation by 2 to align the coefficients of $x$ :

$$
\(2(x+3 y)=2 \times 20 \Longrightarrow 2 x+6 y=40\)
$$


Now subtract the first equation from this:

$$
\(\begin{gathered}
(2 x+6 y)-(2 x+5 y)=40-14 \\
2 x+6 y-2 x-5 y=26 \\
y=26
\end{gathered}\)
$$


Substitute $y=26$ into the second original equation:

$$
\(\begin{gathered}
x+3(26)=20 \\
x+78=20 \\
x=20-78=-58
\end{gathered}\)
$$


Calculate $x+y$ :

$$
\(x+y=-58+26=-32\)
$$


Comparison:
- Quantity A: $\(x+y=-32\)$
- Quantity B : \(-32\)

They are equal.

Final answer:
The two quantities are equal.