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(3/5)^2+(5/3)^-2

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Carcass
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(3/5)^2+(5/3)^-2 [#permalink] New post   06 Dec 2019, 04:33
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\((\frac{3}{5})^2+(\frac{5}{3})^-2=\)

A. \(0\)

B. \(2 (\frac{3}{5})^2\)

C. \((\frac{3}{5}+\frac{5}{3})^2\)

D. \((\frac{3}{5} + \frac{3}{5})^2\)

E. \(1\)

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B
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GreenlightTestPrep
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Re: (3/5)^2+(5/3)^-2 [#permalink] New post   06 Dec 2019, 06:50
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Carcass wrote:
\((\frac{3}{5})^2+(\frac{5}{3})^{-2}=\)

A. \(0\)

B. \(2 (\frac{3}{5})^2\)

C. \((\frac{3}{5}+\frac{5}{3})^2\)

D. \((\frac{3}{5} + \frac{3}{5})^2\)

E. \(1\)

Kudos for the right answer and explanation


Key property: \((\frac{a}{b})^{-n} = (\frac{b}{a})^{n}\)
For example: \((\frac{2}{7})^{-3} = (\frac{7}{2})^{3}\)

So.....

\((\frac{3}{5})^2+(\frac{5}{3})^{-2}=(\frac{3}{5})^2+(\frac{3}{5})^2\)

\(= 2(\frac{3}{5})^2\)

Answer: B

Cheers,
Brent
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Re: (3/5)^2+(5/3)^-2 [#permalink] New post   29 Feb 2024, 08:13
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Re: (3/5)^2+(5/3)^-2 [#permalink]
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