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3+ sqrt of 48/ sqrt of 3
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27 Jun 2022, 03:00
27 Jun 2022, 03:00
1
Expert Reply
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Question Stats:
66% (00:30) correct
33% (00:32) wrong based on 30 sessions
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Quantity A |
Quantity B |
\(\frac{ 3 \sqrt{48 }}{\sqrt{ 3} } \) |
\( 12\) |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Part of the project: GRE QCQ & PS 3 Questions Every One DAILY Challenge - (2022)
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GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
3+ sqrt of 48/ sqrt of 3
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08 Jul 2022, 06:13
08 Jul 2022, 06:13
Expert Reply
\(\frac{3 \sqrt{48}}{\sqrt{3}}\)
Two approaches
\(\frac{3 \sqrt{48}}{\sqrt{3}} * \frac{\sqrt{3}}{\sqrt{3}} = \frac{3 \sqrt{144}}{3} = \frac{3*12}{3}=12\)
OR
factor out the roots
\(\frac{3 \sqrt{2^2*2^2*3}}{\sqrt{3}}= \frac{3*2*2 \sqrt{3}}{\sqrt{3}} =12\)
C is the answer
Two approaches
\(\frac{3 \sqrt{48}}{\sqrt{3}} * \frac{\sqrt{3}}{\sqrt{3}} = \frac{3 \sqrt{144}}{3} = \frac{3*12}{3}=12\)
OR
factor out the roots
\(\frac{3 \sqrt{2^2*2^2*3}}{\sqrt{3}}= \frac{3*2*2 \sqrt{3}}{\sqrt{3}} =12\)
C is the answer
Re: 3+ sqrt of 48/ sqrt of 3
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08 Jul 2022, 06:14
08 Jul 2022, 06:14
Expert Reply
