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3(x – 7) ≥ 9
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23 Jul 2018, 09:54
23 Jul 2018, 09:54
1
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Question Stats:
83% (00:52) correct
16% (01:00) wrong based on 261 sessions
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\(3(x – 7) \geq 9\)
\(0.25y – 3 \leq 1\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Kudos for R.A.E
\(0.25y – 3 \leq 1\)
Quantity A |
Quantity B |
\(x\) |
\(y\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Kudos for R.A.E
Re: 3(x – 7) ≥ 9
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27 Jul 2018, 09:35
27 Jul 2018, 09:35
3
Carcass wrote:
\(3(x – 7) \geq 9\)
\(0.25y – 3 \leq 1\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Kudos for R.A.E
\(0.25y – 3 \leq 1\)
Quantity A |
Quantity B |
\(x\) |
\(y\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Kudos for R.A.E
The first equation can be solved algebraically,
\(3(x – 7) \geq 9\)
or\(x - 7 \geq 3\)
or \(x \geq 10\)
For 2nd equation:
\(0.25y – 3 \leq 1\)
or \(0.25y \leq 4\)
or \(y\leq 16\)
So we cannot reach to a definite solution for this because x can be of any value from 10 and y can be any value less than or equal to 16
So option is D
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
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Re: 3(x – 7) ≥ 9
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11 Apr 2020, 06:33
11 Apr 2020, 06:33
2
Carcass wrote:
\(3(x – 7) \geq 9\)
\(0.25y – 3 \leq 1\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Kudos for R.A.E
\(0.25y – 3 \leq 1\)
Quantity A |
Quantity B |
\(x\) |
\(y\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Kudos for R.A.E
Given: \(3(x – 7) \geq 9\)
Divide both sides of the inequality by \(3\) to get: \(x – 7 \geq 3\)
Add \(7\) to both sides to get: \(x \geq 10\)
Also given: \(0.25y – 3 \leq 1\)
Add \(3\) to both sides to get: \(0.25y \leq 4\)
Multiply both sides by \(4\) to get: \(y \leq 16\)
We now know that \(x \geq 10\) and \(y \leq 16\)
So, for example, it could be the case that x = 12 and y = 12, in which case the two quantities are equal
Or, it could be the case that x = 13 and y = 12, in which case Quantity A is greater
Answer: D
Cheers,
Brent
