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|3 x-5|<16 and |x+2|>1
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18 Sep 2026, 23:17
18 Sep 2026, 23:17
Expert Reply
00:00
Question Stats:
61% (01:31) correct
38% (01:13) wrong based on 13 sessions
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\( |3 x-5|<16\) and \( |x+2|>1 \)
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\( 2x-3\) |
9 |
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
- Part of the project: GRE Daily Quant Challenge ALL 4 CORE QUANT AREAS
- Also replying to the unanswered questions
Re: |3 x-5|<16 and |x+2|>1
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20 Sep 2026, 21:34
20 Sep 2026, 21:34
1
On taking 4 cases, we will arrive at
-11/3 < x < -3 and -1 < x < 7
A a b c d B
2x-3 9
Adding 3 both sides and divide by 2
x 6
When x = 6 —> C
When x = -3.5 —> B
Answer is D
-11/3 < x < -3 and -1 < x < 7
A a b c d B
2x-3 9
Adding 3 both sides and divide by 2
x 6
When x = 6 —> C
When x = -3.5 —> B
Answer is D
gmatclubot
Re: |3 x-5|<16 and |x+2|>1 [#permalink]
20 Sep 2026, 21:34
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