Carcass wrote:
30 liters of a certain drink is to be divided between the students of \(5^{th}\) and \(10^{th}\) class. A school teacher is appointed on that duty. He gave \(\frac{3}{7}\) liter drink to each of \(5^{th}\) class student and then the remaining drink with \(\frac{3}{2}\) liters to each of \(10^{th}\) class student. If there are 21 students of \(5^{th}\) class, then what will be the number of students of \(10^{th}\) class and what will be the percentage to the total number of students ?
Consider all that apply
A. 12 students
B. 14 students
C. 16 students
D. 40%
E. 50%
F. 60 %
Let \(5^{th}\) class students be \(X\) and \(10^{th}\) class students be \(Y\)
Given, \(X = 21\)
So drink given to \(5^{th}\) class students \(= \frac{3}{7}(X) = \frac{3}{7}(21) = 9 \)lts
Drink given to \(10^{th}\) class students = \(30 - 9 = 21\) lts
i.e. \(21 = 3/2(Y)\)
\(Y = 14\)
\(Y\)% \(= \frac{14}{(21+14)}(100) = 40\)%
Hence, option B and D