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Re: 4^13 - 4^12 [#permalink]
2
There are two important "tricks" in this quesiton.

1) You have to use the rule for "distributing a factor" (or whatever is called).

2) You have to realize that the difference between 4^13 and 4^11 is two times 4.

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4^13 - 4^12 [#permalink]
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\(\frac{4^{13}-4^{12}}{4^{11}} = \frac{4^{12}(4-1)}{4^{11}} = \frac{4^{12} \times 3}{4^{11}} = 4 \times 3 = 12\)

The answer is D
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