Carcass wrote:
\(4^5=\frac{4^{20}}{4^x}\)
Quantity A |
Quantity B |
x |
4 |
APPROACH 1: recognize that \(\frac{b^x}{b^y}=b^{x-y}\)
So, if \(\frac{4^{20}}{4^x}=4^5\), then we can rewrite it as \(4^{20-x}=4^5\), in which case, we can see that \(x = 15\)
Answer: A
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APPROACH 2:
GIVEN: \(4^5=\frac{4^{20}}{4^x}\)
Multiply both sides by \(4^x\) to get: \((4^5)(4^x)=4^{20}\)
Simplify left side to get: \(4^{5+x}=4^{20}\)
This means: \(5+x = 20\), which means \(x=15\)
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Answer: A
Cheers,
Brent