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5 sqrt3x
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Updated on: 24 Feb 2022, 10:01
Updated on: 24 Feb 2022, 10:01
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\(x >0\)
A) The quantity in Column A is greater.
B) The quantity in Column B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(5 \sqrt{3x}\) |
\(3 \sqrt{5x} \) |
A) The quantity in Column A is greater.
B) The quantity in Column B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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5 sqrt3x
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24 Feb 2022, 09:49
24 Feb 2022, 09:49
Carcass wrote:
\(x >0\)
Quantity A |
Quantity B |
\(5 \sqrt{3x}\) |
\(3 \sqrt{5x} \) |
Property: If x and y are positive, and \(0< x^2 < y^2\), then \(0< x < y\)
Given:
Quantity A: \(5 \sqrt{3x}\)
Quantity B: \(3 \sqrt{5x} \)
Square both quantities to get:
Quantity A: \((5 \sqrt{3x})^2\)
Quantity B: \((3 \sqrt{5x})^2\)
Simplify both quantities:
Quantity A: \((25)(3x)\)
Quantity B: \((9)(5x) \)
Simplify more:
Quantity A: \(75x\)
Quantity B: \(45x \)
Since we are told \(x > 0\), we can safely divide both quantities by x to get:
Quantity A: \(75\)
Quantity B: \(45 \)
Answer: A
gmatclubot
5 sqrt3x [#permalink]
24 Feb 2022, 09:49
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