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(6 + 3) × 5 – 6 ÷ 2 + 3

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(6 + 3) × 5 – 6 ÷ 2 + 3 [#permalink] New post   01 Jan 2021, 12:55
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Quantity A
Quantity B
\((6 + 3) × 5 – 6 ÷ 2 + 3^2\)
\(6 + 3 × 5 – 6 ÷ 2 + 3^2 \)




A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

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rx10
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Re: (6 + 3) × 5 – 6 ÷ 2 + 3 [#permalink] New post   02 Jan 2021, 08:36
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The order is - First bracket then division then multiplication then summation and last subtraction.

Qt A

\((6 + 3) × 5 – 6 ÷ 2 + 3\)

\((6 + 3) × 5 – 3 + 3\)

\((9) × 5 – 3 + 3\)

\(45 - 6 = 39\)

Qt B

\(6 + 3 × 5 – 6 ÷ 2 + 3^2 \)

\(6 + 3 × 5 - 3 + 9\)

\(6 + 15 - 12\)

\(21 - 12 = 9\)

Answer A
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Re: (6 + 3) × 5 – 6 ÷ 2 + 3 [#permalink] New post   03 Jan 2021, 14:19
rx10 wrote:
The order is - First bracket then division then multiplication then summation and last subtraction.

Qt A

\((6 + 3) × 5 – 6 ÷ 2 + 3\)

\((6 + 3) × 5 – 3 + 3\)

\((9) × 5 – 3 + 3\)

\(45 - 6 = 39\)

Qt B

\(6 + 3 × 5 – 6 ÷ 2 + 3^2 \)

\(6 + 3 × 5 - 3 + 9\)

\(6 + 15 - 12\)

\(21 - 12 = 9\)

Answer A


Hi, Thank you for sharing answer.
Just confirmation, I think you missed the calculation of A), you did add 3 in last, but it should be 9,3^2, I think.
Also, for B), I think , -3 + 9 should be +6 , not -12.

It does not change the conclusion, though.
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Re: (6 + 3) × 5 – 6 ÷ 2 + 3 [#permalink] New post   03 Jan 2021, 14:25
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I would like to save time as much as possible for this kind of question.
We only need to focus on a part of equation. The latter part after "-" is same and will not change the conclusion.

A) (6+3) x 5 = 45
B) 6 + 3 x 5 = 21

So A) is bigger than B),
Answer : A)
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gmatclubot
Re: (6 + 3) × 5 – 6 ÷ 2 + 3 [#permalink]
03 Jan 2021, 14:25
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