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(6 + 3) × 5 – 6 ÷ 2 + 3
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01 Jan 2021, 12:55
01 Jan 2021, 12:55
Expert Reply
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Question Stats:
84% (00:54) correct
16% (01:37) wrong based on 25 sessions
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Quantity A |
Quantity B |
\((6 + 3) × 5 – 6 ÷ 2 + 3^2\) |
\(6 + 3 × 5 – 6 ÷ 2 + 3^2 \) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Re: (6 + 3) × 5 – 6 ÷ 2 + 3
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02 Jan 2021, 08:36
02 Jan 2021, 08:36
1
The order is - First bracket then division then multiplication then summation and last subtraction.
Qt A
\((6 + 3) × 5 – 6 ÷ 2 + 3\)
\((6 + 3) × 5 – 3 + 3\)
\((9) × 5 – 3 + 3\)
\(45 - 6 = 39\)
Qt B
\(6 + 3 × 5 – 6 ÷ 2 + 3^2 \)
\(6 + 3 × 5 - 3 + 9\)
\(6 + 15 - 12\)
\(21 - 12 = 9\)
Answer A
Qt A
\((6 + 3) × 5 – 6 ÷ 2 + 3\)
\((6 + 3) × 5 – 3 + 3\)
\((9) × 5 – 3 + 3\)
\(45 - 6 = 39\)
Qt B
\(6 + 3 × 5 – 6 ÷ 2 + 3^2 \)
\(6 + 3 × 5 - 3 + 9\)
\(6 + 15 - 12\)
\(21 - 12 = 9\)
Answer A
Re: (6 + 3) × 5 – 6 ÷ 2 + 3
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03 Jan 2021, 14:19
03 Jan 2021, 14:19
rx10 wrote:
The order is - First bracket then division then multiplication then summation and last subtraction.
Qt A
\((6 + 3) × 5 – 6 ÷ 2 + 3\)
\((6 + 3) × 5 – 3 + 3\)
\((9) × 5 – 3 + 3\)
\(45 - 6 = 39\)
Qt B
\(6 + 3 × 5 – 6 ÷ 2 + 3^2 \)
\(6 + 3 × 5 - 3 + 9\)
\(6 + 15 - 12\)
\(21 - 12 = 9\)
Answer A
Qt A
\((6 + 3) × 5 – 6 ÷ 2 + 3\)
\((6 + 3) × 5 – 3 + 3\)
\((9) × 5 – 3 + 3\)
\(45 - 6 = 39\)
Qt B
\(6 + 3 × 5 – 6 ÷ 2 + 3^2 \)
\(6 + 3 × 5 - 3 + 9\)
\(6 + 15 - 12\)
\(21 - 12 = 9\)
Answer A
Hi, Thank you for sharing answer.
Just confirmation, I think you missed the calculation of A), you did add 3 in last, but it should be 9,3^2, I think.
Also, for B), I think , -3 + 9 should be +6 , not -12.
It does not change the conclusion, though.
