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7y - 3 < = 4y + 9
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23 Jul 2018, 09:32
23 Jul 2018, 09:32
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Question Stats:
71% (00:31) correct
28% (00:34) wrong based on 237 sessions
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\(7y - 3 \leq 4y + 9\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Kudos for R.A.E
Quantity A |
Quantity B |
y |
4 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Kudos for R.A.E
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Joined: 10 Apr 2015
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Re: 7y - 3 < = 4y + 9
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03 Aug 2018, 11:47
03 Aug 2018, 11:47
1
Carcass wrote:
\(7y - 3 \leq 4y + 9\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Kudos for R.A.E
Quantity A |
Quantity B |
y |
4 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Kudos for R.A.E
GIVEN: 7y - 3 ≤ 4y + 9
Subtract 4y from both sides: 3y - 3 ≤ 9
Add 3 to both sides: 3y ≤ 12
Divide both sides by 3 to get: y ≤ 4
This means that y COULD equal 4, in which case the two quantities are EQUAL
It also means that y COULD equal 3, in which case the Quantity B IS GREATER
Answer: D
Cheers,
Brent
7y - 3 < = 4y + 9
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20 Jun 2023, 00:50
20 Jun 2023, 00:50
1
\(7y-3 \leq 4y + 9\)
\(7y-4y \leq 9+3\)
\(3y \leq 12\)
\(y \leq 4\)
\(y = 4 \) in which case C is true
and \(y<4\) in which case B is true.
Therefore, the correct choice is D.
\(7y-4y \leq 9+3\)
\(3y \leq 12\)
\(y \leq 4\)
\(y = 4 \) in which case C is true
and \(y<4\) in which case B is true.
Therefore, the correct choice is D.
