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A 7 meter long wire is cut into two pieces at an arbitrary point. The
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11 Aug 2021, 08:35
11 Aug 2021, 08:35
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A 7 meter long wire is cut into two pieces at an arbitrary point. The longer piece is then used to form a square.
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Quantity A |
Quantity B |
Probability that the area of the square will be more than 1 \(m^2\) |
\(\frac{4}{5}\) |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
Re: A 7 meter long wire is cut into two pieces at an arbitrary point. The
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12 Aug 2021, 05:04
12 Aug 2021, 05:04
1
Explanation:
Note: Longer piece has to be greater than 3.5m
Let the increment in the pieces be 0.5m
So, total outcomes could be 4.0, 4.5, 5.0, 5.5, 6.0, 6.5, 7.0 i.e. 7 outcomes
Now, if the area has to be greater than 1\(m^2\), each side should be greater than 1. Therefore, perimeter of the square has to be greater than 4.
So, favorable outcomes could be 4.5, 5.0, 5.5, 6.0, 6.5, 7.0 i.e. 6 outcomes
Required probability = \(\frac{6}{7}\)
Col. A: 0.85
Col. B: 0.80
Hence, option A
Note: Longer piece has to be greater than 3.5m
Let the increment in the pieces be 0.5m
So, total outcomes could be 4.0, 4.5, 5.0, 5.5, 6.0, 6.5, 7.0 i.e. 7 outcomes
Now, if the area has to be greater than 1\(m^2\), each side should be greater than 1. Therefore, perimeter of the square has to be greater than 4.
So, favorable outcomes could be 4.5, 5.0, 5.5, 6.0, 6.5, 7.0 i.e. 6 outcomes
Required probability = \(\frac{6}{7}\)
Col. A: 0.85
Col. B: 0.80
Hence, option A
General Discussion
Re: A 7 meter long wire is cut into two pieces at an arbitrary point. The
[#permalink]
11 Aug 2021, 10:11
11 Aug 2021, 10:11
is it d.
