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A 9 ft x 4 ft poster covers 18% of a
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05 Apr 2025, 10:30
05 Apr 2025, 10:30
Expert Reply
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Question Stats:
100% (00:29) correct
0% (00:00) wrong based on 2 sessions
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A $\(9 \mathrm{ft} \times 4 \mathrm{ft}\)$ poster covers $\(18 \%\)$ of a rectangular wall. What is the approximate area of the wall (in sq.feet)?
(A) 126
(B) 156
(C) 160
(D) 190
(E) 200
(A) 126
(B) 156
(C) 160
(D) 190
(E) 200
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Re: A 9 ft x 4 ft poster covers 18% of a
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08 Apr 2025, 13:03
08 Apr 2025, 13:03
1
The 9x4 poster has an area of 36 sq ft.
Let a = the area of the rectangular wall.
If 36 sq ft = 0.18 * a, then a = 200 sq ft.
Let a = the area of the rectangular wall.
If 36 sq ft = 0.18 * a, then a = 200 sq ft.
Re: A 9 ft x 4 ft poster covers 18% of a
[#permalink]
09 Apr 2025, 04:30
09 Apr 2025, 04:30
Expert Reply
The area of the poster is $\(9 \times 4=36\)$ square feet. .
It is given that $\(18 \%\)$ of the area of the wall is 36 . Therefore, $\(100 \%\)$ of the area of the wall is $\(\frac{100}{18} \times 36=200\)$. Thus, the correct answer choice is $E$.
It is given that $\(18 \%\)$ of the area of the wall is 36 . Therefore, $\(100 \%\)$ of the area of the wall is $\(\frac{100}{18} \times 36=200\)$. Thus, the correct answer choice is $E$.
