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Re: A and B are graphical representations of normally distribute [#permalink]
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Any explanations for why option C is correct?
Do we consider the X-axis value of the protruded parts in A and B curves? If yes, then C is true.

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Re: A and B are graphical representations of normally distribute [#permalink]
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The mean of a normal curve is the point along the horizontal axis below the “peak” of the curve. Red and blue lines, respectively

B is to the right of the highest point of curve A, so the mean of Y is larger than the mean of X.

Ask for further assistance.

Attachment:
#GREpracticequestion A and B are graphical representations of normally.PNG
#GREpracticequestion A and B are graphical representations of normally.PNG [ 77.73 KiB | Viewed 7399 times ]


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Re: A and B are graphical representations of normally distribute [#permalink]
Carcass wrote:
The mean of a normal curve is the point along the horizontal axis below the “peak” of the curve. Red and blue lines, respectively

B is to the right of the highest point of curve A, so the mean of Y is larger than the mean of X.

Ask for further assistance.

Attachment:
#GREpracticequestion A and B are graphical representations of normally.PNG


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do not get it, please elaborate again
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Re: A and B are graphical representations of normally distribute [#permalink]
Why B is not the answer?
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Re: A and B are graphical representations of normally distribute [#permalink]
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daina1323031 wrote:
Why B is not the answer?



B is to the right of the highest point of curve A, so the mean of Y is larger than the mean of X.

See my explanation and graph above

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Re: A and B are graphical representations of normally distribute [#permalink]
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daina1323031 wrote:
Why B is not the answer?


B. The probability that Y falls within 2 standard deviations of its mean is greater than the probability that X falls within 2 standard deviations of its mean.

Image

For ALL normal distributions, the probability that a selected value falls within two standard deviations of the mean is ALWAYS 96% (14% + 34% + 34% + 14% = 96%)
We know this because, for all normal distributions, 96% of the population is within two standard deviations of the mean of the population.

Since the probability that Y falls within 2 standard deviations of its mean EQUALS the probability that X falls within 2 standard deviations of its mean, statement B is false.
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Re: A and B are graphical representations of normally distribute [#permalink]
Carcass wrote:
The mean of a normal curve is the point along the horizontal axis below the “peak” of the curve. Red and blue lines, respectively

B is to the right of the highest point of curve A, so the mean of Y is larger than the mean of X.

Ask for further assistance.

Attachment:
#GREpracticequestion A and B are graphical representations of normally.PNG


Regards


Isn't the line below the "peak" called the median, and not the mean?
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