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a and b are positive integers, and 110a + 17b = 4417

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a and b are positive integers, and 110a + 17b = 4417 [#permalink] New post   14 Nov 2020, 09:36
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a and b are positive integers, and \(110a + 17b = 4417 \)


Quantity A
Quantity B
\(a+b\)
41



A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Source: 320 GRE Math Questions
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Re: a and b are positive integers, and 110a + 17b = 4417 [#permalink] New post   16 Nov 2020, 18:20
I am only getting C :(
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Re: a and b are positive integers, and 110a + 17b = 4417 [#permalink] New post   16 Nov 2020, 19:06
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ishitadatta wrote:
I am only getting C :(


means you do not know why is D ?
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Re: a and b are positive integers, and 110a + 17b = 4417 [#permalink] New post   16 Nov 2020, 20:04
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ishitadatta wrote:
I am only getting C :(


Me too.
It seems that a = 40 and b = 1 is the only solution, in which case the answer is D.
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Re: a and b are positive integers, and 110a + 17b = 4417 [#permalink] New post   16 Nov 2020, 20:24
Carcass wrote:
ishitadatta wrote:
I am only getting C :(


means you do not know why is D ?


That's right. Why is it D?
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Re: a and b are positive integers, and 110a + 17b = 4417 [#permalink] New post   16 Nov 2020, 20:25
GreenlightTestPrep wrote:
ishitadatta wrote:
I am only getting C :(


Me too.
It seems that a = 40 and b = 1 is the only solution, in which case the answer is D.


If this is the only solution i.e, if a+b=40+1=41, then how is it D?
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Re: a and b are positive integers, and 110a + 17b = 4417 [#permalink] New post   17 Nov 2020, 00:25
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The stem and the answer are correct.

Fake question from 320 Math book.

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Re: a and b are positive integers, and 110a + 17b = 4417 [#permalink]
17 Nov 2020, 00:25
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