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|a|/b > 1 and a+b<0
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09 Aug 2018, 03:49
09 Aug 2018, 03:49
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Question Stats:
76% (00:55) correct
23% (01:00) wrong based on 296 sessions
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\(\frac{|a|}{b} > 1\) and \(a+b<0\)
\(b \neq 0\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Kudos for R.A.E
_________________
\(b \neq 0\)
Quantity A |
Quantity B |
a |
0 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Kudos for R.A.E
_________________
Re: |a|/b > 1 and a+b<0
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23 Apr 2019, 06:08
23 Apr 2019, 06:08
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Bookmarks
Carcass wrote:
\(\frac{|a|}{b} > 1\) and \(a+b<0\)
\(b \neq 0\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Kudos for R.A.E
\(b \neq 0\)
Quantity A |
Quantity B |
a |
0 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Kudos for R.A.E
GIVEN: \(\frac{|a|}{b} > 1\)
In other words, \(\frac{|a|}{b}\) is POSITIVE
Since |a| must be POSITIVE, we know that b must also be POSITIVE
GIVEN: \(a+b<0\)
We already know that b is POSITIVE
Since the SUM a+b is negative, we know that a is NEGATIVE
We have:
QUANTITY A: some NEGATIVE number
QUANTITY B: 0
Answer: B
Cheers,
Brent
_________________
General Discussion
Re: |a|/b > 1 and a+b<0
[#permalink]
09 Aug 2018, 15:31
09 Aug 2018, 15:31
2
Carcass wrote:
\(\frac{|a|}{b} > 1\) and \(a+b<0\)
\(b \neq 0\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Kudos for R.A.E
\(b \neq 0\)
Quantity A |
Quantity B |
a |
0 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Kudos for R.A.E
Given
\(\frac{|a|}{b} > 1\) and \(a+b<0\)
|x| is always positive.
So, b has to be positive.
but we know a + b <0. So, a has to be negative.
0 is greater than any negative value.
The best answer is B.
Re: |a|/b > 1 and a+b<0
[#permalink]
12 Sep 2023, 18:51
12 Sep 2023, 18:51
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
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