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a > b and |b| > |a|
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13 Jan 2023, 06:31
13 Jan 2023, 06:31
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68% (01:32) wrong based on 50 sessions
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\(a > b\) and \(|b| > |a|\)
A) The quantity in Column A is greater.
B) The quantity in Column B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(ab^2\) |
\(a^2b \) |
A) The quantity in Column A is greater.
B) The quantity in Column B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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a > b and |b| > |a|
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14 Jan 2023, 21:53
14 Jan 2023, 21:53
1
Given that \(a > b\) and \(|b| > |a|\)
Now, this is possible only when b is a big negative number and a is either positive, zero or a smaller negative number than b such that |b| > |a|
Ex 1: b = -3, a = 1 => a > b and |b| > |a|
Ex 2: b = -3, a = -1 => a > b and |b| > |a|
Quantity A = \(ab^2\) and Quantity B = \(a^2b \)
Ex 1: b = -3, a = 1
\(ab^2\) = \(1*(-3)^2\) = 9
\(a^2b\) = \(1^2*(-3) \) = -3
Quantity A > Quantity B
Ex 2: b = -3, a = -1
\(ab^2\) = \(-1*(-3)^2\) = -9
\(a^2b\) = \((-1)^2*(-3) \) = -3
Quantity B > Quantity A
Clearly, we cannot conclude anything concrete from this so both Quantities can be greater.
So, Answer will be D
Hope it helps!
Watch the following video to learn the Basics of Absolute Values
Now, this is possible only when b is a big negative number and a is either positive, zero or a smaller negative number than b such that |b| > |a|
Ex 1: b = -3, a = 1 => a > b and |b| > |a|
Ex 2: b = -3, a = -1 => a > b and |b| > |a|
Quantity A = \(ab^2\) and Quantity B = \(a^2b \)
Ex 1: b = -3, a = 1
\(ab^2\) = \(1*(-3)^2\) = 9
\(a^2b\) = \(1^2*(-3) \) = -3
Quantity A > Quantity B
Ex 2: b = -3, a = -1
\(ab^2\) = \(-1*(-3)^2\) = -9
\(a^2b\) = \((-1)^2*(-3) \) = -3
Quantity B > Quantity A
Clearly, we cannot conclude anything concrete from this so both Quantities can be greater.
So, Answer will be D
Hope it helps!
Watch the following video to learn the Basics of Absolute Values
