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A, B and C are the three interior angles in a triangle
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27 Jan 2025, 23:38
27 Jan 2025, 23:38
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57% (01:00) correct
42% (00:08) wrong based on 7 sessions
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$\(A, B\)$ and $\(C\)$ are the three interior angles in a triangle such that $\(A<B<C\)$.
Quantity A |
Quantity B |
A+B |
C |
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Re: A, B and C are the three interior angles in a triangle
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03 Mar 2025, 09:32
03 Mar 2025, 09:32
Expert Reply
The three interior angles $\(\mathrm{A}, \mathrm{B} \& \mathrm{C}\)$ of a triangle are such that $\(\mathrm{A}<\mathrm{B}<\mathrm{C}\)$; we need to compare the value of $\(A+B\)$ with the value of $\(C\)$.
Since the values of angles $\(A, B \& C\)$ is not known, a unique comparison cannot be formed.
For example if we take $\(\mathrm{A}=30, \mathrm{~B}=60 \& \mathrm{C}=90\)$, we get $\(\mathrm{A}+\mathrm{B}=30+60=90\)$ which is same as $\(C=90\)$. (The sum of the interior angles of a triangle is 180 degrees)
But if we take $\(A=20, B=30 \& C=130\)$, we get $\(A+B=20+30=50\)$ which is less than $\(C=\)$ 130.
Hence the answer is (D).
Since the values of angles $\(A, B \& C\)$ is not known, a unique comparison cannot be formed.
For example if we take $\(\mathrm{A}=30, \mathrm{~B}=60 \& \mathrm{C}=90\)$, we get $\(\mathrm{A}+\mathrm{B}=30+60=90\)$ which is same as $\(C=90\)$. (The sum of the interior angles of a triangle is 180 degrees)
But if we take $\(A=20, B=30 \& C=130\)$, we get $\(A+B=20+30=50\)$ which is less than $\(C=\)$ 130.
Hence the answer is (D).
gmatclubot
Re: A, B and C are the three interior angles in a triangle [#permalink]
03 Mar 2025, 09:32
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