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a b + b × (b3 a) ÷ b must be equal to A. a (b + b) × (b3 a)
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16 Jul 2022, 23:14
16 Jul 2022, 23:14
1
Expert Reply
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Question Stats:
77% (01:31) correct
22% (00:47) wrong based on 36 sessions
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\(a – b + b × (b^3– a) ÷ b\) must be equal to
A. \(a – (b + b) × (b^3– a) ÷ b\)
B. \(–b + b^3\)
C. \(–b3\)
D. \(a × (b^3– a) ÷ b\)
E. \(a × (b^4– a) ÷ b\)
A. \(a – (b + b) × (b^3– a) ÷ b\)
B. \(–b + b^3\)
C. \(–b3\)
D. \(a × (b^3– a) ÷ b\)
E. \(a × (b^4– a) ÷ b\)
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a b + b × (b3 a) ÷ b must be equal to A. a (b + b) × (b3 a)
[#permalink]
20 Jul 2022, 07:20
20 Jul 2022, 07:20
1
Expert Reply
Carcass wrote:
\(a – b + b × (b^3– a) ÷ b\) must be equal to
A. \(a – (b + b) × (b^3– a) ÷ b\)
B. \(–b + b^3\)
C. \(–b3\)
D. \(a × (b^3– a) ÷ b\)
E. \(a × (b^4– a) ÷ b\)
A. \(a – (b + b) × (b^3– a) ÷ b\)
B. \(–b + b^3\)
C. \(–b3\)
D. \(a × (b^3– a) ÷ b\)
E. \(a × (b^4– a) ÷ b\)
Use PEMDAS Rule
Parenthesis
Exponents
Multiplication and Division
Addition and subtraction
\(a – b + b × b^3 – a ÷ b\)
\(\frac{b^4}{b} +a -a -b = b^3 -b\)
Answer: B
gmatclubot
a b + b × (b3 a) ÷ b must be equal to A. a (b + b) × (b3 a) [#permalink]
20 Jul 2022, 07:20
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