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a < b < c
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21 Oct 2018, 08:17
21 Oct 2018, 08:17
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Question Stats:
53% (01:08) correct
46% (00:54) wrong based on 222 sessions
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\(a < b < c\)
\(b+c<0\)
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
\(b+c<0\)
Quantity A |
Quantity B |
ac |
0 |
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
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Re: a < b < c
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23 Oct 2018, 05:34
23 Oct 2018, 05:34
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Carcass wrote:
\(a < b < c\)
\(b+c<0\)
\(b+c<0\)
Quantity A |
Quantity B |
ac |
0 |
Notice that we don't have much information about the 3 variables a, b and c
Since b + c < 0, we know that at least one variable is negative (which means a must be negative), but that's pretty much it.
The missing part here is that we don't really know whether c is positive or negative.
Given the absences of solid information about c, we might solve this question by testing values
Case i: a = -3, b = -2, and c = 1 (these values satisfy the given information). We get:
Quantity A: ac = (-3)(1) = -3
Quantity B: 0
In this case, Quantity B is greater
Case ii: a = -3, b = -2, and c = -1 (these values satisfy the given information). We get:
Quantity A: ac = (-3)(-1) = 3
Quantity B: 0
In this case, Quantity A is greater
Answer: D
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Re: a < b < c
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23 Oct 2018, 20:28
23 Oct 2018, 20:28
if b+c<0, and a<b<c, then we know that A and B MUST be negative numbers and C can be a number ranging all the way from a negative up to a huge positive (just as long as the negative value of B is a larger negative than C is a positive such that their sum would still be less than 0). Quantity A being AC therefore could either be a negative*negative=positive (in which case quantity A>B) or a negative*positive =negative (in which case quantity A<B). Since we don't have a definitive answer, the correct choice is D.
