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a>b>k>0
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08 Mar 2021, 07:30
08 Mar 2021, 07:30
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\(a>b>k>0\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Quantity A |
Quantity B |
\(\frac{a}{b}\) |
\(\frac{(a+k)}{(b+k)}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
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Re: a>b>k>0
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08 Mar 2021, 07:36
08 Mar 2021, 07:36
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Carcass wrote:
\(a>b>k>0\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(\frac{a}{b}\) |
\(\frac{(a+k)}{(b+k)}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Let's solve this in 10 seconds;
Col. A: \(\frac{a}{b}\)
Col. B: \(\frac{(a+k)}{(b+k)}\)
Cross-multiply the denominators;
Col. A: \(ab + ak\)
Col. B: \(ab + bk\)
Subtracting \(ab\) from both the sides;
Col. A: \(ak\)
Col. B: \(bk\)
Dividing by \(k\) both the sides;
Col. A: \(a\)
Col. B: \(b\)
Hence, option A
Re: a>b>k>0
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05 Aug 2022, 08:48
05 Aug 2022, 08:48
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