Carcass wrote:
A bag contains 10 red jellybeans and 10 blue jellybeans. If 3 jellybeans are removed one at a time, at random and are not replaced, what is the probability that all 3 jellybeans removed from the bag are blue?
A. 9/100
B. 2/19
C. 1/8
D. 3/20
E. 3/10
P(all 3 beans are blue) = P(1st bean is blue
AND 2nd bean is blue
AND 3rd bean is blue)
= P(1st bean is blue)
x P(2nd bean is blue)
x P(3rd bean is blue)
= 10/20
x 9/19
x 8/18
= 2/19
Answer: B
Cheers,
Brent