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A bag contains 10 red jellybeans and 10 blue jellybeans. If 3 jellybea
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06 Oct 2021, 09:18
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A bag contains 10 red jellybeans and 10 blue jellybeans. If 3 jellybeans are removed one at a time, at random and are not replaced, what is the probability that all 3 jellybeans removed from the bag are blue?
Re: A bag contains 10 red jellybeans and 10 blue jellybeans. If 3 jellybea
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06 Oct 2021, 09:32
Carcass wrote:
A bag contains 10 red jellybeans and 10 blue jellybeans. If 3 jellybeans are removed one at a time, at random and are not replaced, what is the probability that all 3 jellybeans removed from the bag are blue?
A. 9/100 B. 2/19 C. 1/8 D. 3/20 E. 3/10
P(all 3 beans are blue) = P(1st bean is blue AND 2nd bean is blue AND 3rd bean is blue) = P(1st bean is blue) x P(2nd bean is blue) x P(3rd bean is blue) = 10/20 x 9/19 x 8/18 = 2/19 Answer: B
Cheers, Brent
gmatclubot
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