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A bag contains x blue chips and y red chips. If the probability 3 of s

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A bag contains x blue chips and y red chips. If the probability 3 of s [#permalink] New post   12 Oct 2022, 06:09
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A bag contains x blue chips and y red chips. If the probability of selecting a red chip at random is 3/7, then x/y=

A. 7/11
B. 3/4
C. 7/4
D. 4/3
E. 11/7


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Re: A bag contains x blue chips and y red chips. If the probability 3 of s [#permalink] New post   12 Oct 2022, 10:47
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Blue chips = x , Red chips= y
P(y) =3/7 = (y)/(x+y)
3/7 =y/(x+y)
y= 3 , (x+y) =7 ,x=4
.: x/y =4/3

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Re: A bag contains x blue chips and y red chips. If the probability 3 of s [#permalink]
12 Oct 2022, 10:47
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