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A bag contains x blue chips and y red chips. If the probability 3 of s
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12 Oct 2022, 06:09
12 Oct 2022, 06:09
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Question Stats:
62% (00:42) correct
37% (00:25) wrong based on 24 sessions
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A bag contains x blue chips and y red chips. If the probability of selecting a red chip at random is 3/7, then x/y=
A. 7/11
B. 3/4
C. 7/4
D. 4/3
E. 11/7
A. 7/11
B. 3/4
C. 7/4
D. 4/3
E. 11/7
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GRE Math Essentials (2022)
GRE Geometry Formulas
GRE - Math Book
Re: A bag contains x blue chips and y red chips. If the probability 3 of s
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12 Oct 2022, 10:47
12 Oct 2022, 10:47
1
Blue chips = x , Red chips= y
P(y) =3/7 = (y)/(x+y)
3/7 =y/(x+y)
y= 3 , (x+y) =7 ,x=4
.: x/y =4/3
Answer D
Posted from my mobile device
P(y) =3/7 = (y)/(x+y)
3/7 =y/(x+y)
y= 3 , (x+y) =7 ,x=4
.: x/y =4/3
Answer D
Posted from my mobile device
Re: A bag contains x blue chips and y red chips. If the probability 3 of s
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29 Jun 2025, 11:37
29 Jun 2025, 11:37
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