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A beaker was filled with a mixture of 40 liters of water and a liquid
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02 Dec 2023, 15:17
Given that the mixture was in a ratio of 3:5, we can set up this fraction:
percent of original amount of mixture evaporated = \(10(\frac{3}{8}*40*0.02+\frac{5}{8}*40*0.05)/40=0.3875=38.75%\)
Note about solving this is that you don't need to know the actual volume of the initial mixture in order to find the solution, since it's asking for a percent of the original, not an actual value. If we weren't given 40 as the initial volume, you could still set up the fraction as:
\(\frac{10(3x*0.02+5x*0.05)}{8x}=0.3875\)